Dynamic universe without gravity, by Aetzbar --------------------------------------------------1 .

Each star has its Material quantity ( M – Newtonian view)

The stars are moving and never stop.

Stars move like a screw – turn and advanced.

Each star is a central star and side star, at the same time.(Copernican view)

The Sun is a central star for the Earth ,and Earth is a central star for the Moon.

The Earth is a side star for the Sun, and the Moon is a side star for the Earth.

Side star revolves around central stare, with lap time T

Let's say that the sun is a point and earth as a point

If we move away from the sun,the distance D will increase from zero km to infinity km

lap time T will increase (from zero hours to infinity hours)

If we move away from the Earth,( D will increase from zero km to infinity km )

lap time T will increase (from zero hours to infinity hours)

The Sun has a unique fit between D and T, and the Earth has a unique fit of D and T.

Each star has its unique fit between D and T.

Kepler fined the formula of the stars D^3 : T^2 = P

P is a unique number of star, that represents a unique fit between D and T.

There is a link between M of star to P of star ( M1 : M2 = P1 : P2 )

How to get the P of earth ?

The earth is a central star for the moon.

Moon is far from earth D = 384000 km, and time it orbited the earth T = 672 hours.

P of Earth = 384000^3 : 672^2 = 1.25*10^11

Dynamic universe without gravity, by Aetzbar ------------------------------------------------ 2

Finding p of the Sun.

The Sun is a central star for the earth (with the moon moves around)

P is obtained by the distance ( Earth – Sun) and time of 1 year in hours.

P of Sun = 429*10^14

Each star has also its Cycle time ( marked ]T[ )

Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a

Tunnel that reaches the other side of the earth. This ball will illustrated a pendulum

Movement ( of 1.4 hours ) between the two openings of the tunnel.

The cycle time of the Earth will be 1.4 hours.

each star has its Cycle time.

M of star determines its ]T[ , by the formula M* ]T[^2 = K (constant)

Because M1 : M2 = P1 : P2

We have the formula P* ]T[^2 = K

According to P of Earth and ]T[ of Earth , K = 2.5*10^11

With the formula P* ]T[^2 = 2.5 *10^11 can calculate ]T[ of Sun = 8.7 seconds

Natural Physical Constant

The formula P* ]T[^2 = 2.5*10^11

is the formula (D^3 : T^2)* ]T[^2 = 2.5 * 10^11

The formula shows that the situation of T = ]T[ appears at the distance of 6300 km, from

the center of each star.

D^3 = 2.5*10^11

D = 6300 km

Thererfor , 6300 km is a Natural Physical Constant.

Dynamic universe without gravity, by Aetzbar ------------------------------------------------ 3

The equality of times law

The equality………. Lap time = Cycle time ….( or ]T[ = T ) will appear only at

D= 6300 km, from the center of each star.

6300 km is a Natural Physical Constant.

The equality of times law determines that each star has a unique fit between D and T